-3x^2+183=0

Solution for -3x^2+183=0 equation:

-3x^2+183=0

a = -3; b = 0; c = +183;
Δ = b2-4ac
Δ = 02-4·(-3)·183
Δ = 2196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2196}=\sqrt{36*61}=\sqrt{36}*\sqrt{61}=6\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{61}}{2*-3}=\frac{0-6\sqrt{61}}{-6}
=-\frac{6\sqrt{61}}{-6}
=-\frac{\sqrt{61}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{61}}{2*-3}=\frac{0+6\sqrt{61}}{-6}
=\frac{6\sqrt{61}}{-6}
=\frac{\sqrt{61}}{-1}
$